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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    An army vehicle of mass 1000 kg is moving with a velocity of 10 m/s and is acted upon by a forward force of 1000  N due to the engine and a retarding force of 500 N due to friction. What will be its velocity after 10 s                        [Pb. PMT 2000]

    A)             5 m/s  

    B)             10 m/s

    C)             15 m/s

    D)             20 m/s

    Correct Answer: C

    Solution :

                    \[v=u+\frac{F}{m}t=10+\left( \frac{1000-500}{1000} \right)\times 10=15\,m/s\]


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