JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A force of 10 Newton acts on a body of mass 20kg for 10 seconds.  Change in its momentum is       [MP PET 2002]

    A)             5 \[kg\,m/s\]

    B)               \[100kg\,m/s\]

    C)             \[200\,kg\,m/s\]

    D)               1000 \[kg\,m/s\]

    Correct Answer: B

    Solution :

                    \[dp=F\times dt=10\times 10=100\ kg\ m/s\]


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