JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A body of mass 2 kg is hung on a spring balance mounted vertically in a lift. If the lift descends with an acceleration equal to the acceleration due to gravity ?g?, the reading on the spring balance will be                          [NCERT 1977]

    A)                         2 kg                 

    B)                         \[(4\times g)\,kg\]            

    C)                         \[(2\times g)\,kg\]            

    D)                           Zero            

    Correct Answer: D

    Solution :

                                Reading on the spring balance = m (g ? a) and since a = g  \ Force = 0


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