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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A man weighs \[80kg.\] He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of \[5m/{{s}^{2}}.\] What would be the reading on the scale. \[(g=10m/{{s}^{2}})\]                             [CBSE PMT 2003]

    A)             400 N 

    B)             800 N

    C)             1200 N

    D)             Zero

    Correct Answer: C

    Solution :

                    For accelerated upward motion             \[R=m\,(g+a)=80\,(10+5)=1200\,N\]


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