A) 1
B) 2
C) 4
D) 0.5
Correct Answer: A
Solution :
Opposing force \[F=u\ \left( \frac{dm}{dt} \right)=2\times 0.5=1\ N\] \[\left( \text{As,}\ F=u\frac{du}{dt} \right)\] So same amount of force is required to keep the belt moving at 2 m/sYou need to login to perform this action.
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