A) 1 : 9
B) 1 : 3
C) 3 : 1
D) 9 : 1
Correct Answer: D
Solution :
When trolley are released then they posses same linear momentum but in opposite direction. Kinetic energy acquired by any trolley will dissipate against friction. \[\therefore \] \[\mu \,mg\,s=\frac{{{p}^{2}}}{2m}\] Þ \[s\propto \frac{1}{{{m}^{2}}}\] [As P and u are constants] Þ \[\frac{{{s}_{1}}}{{{s}_{2}}}={{\left( \frac{{{m}_{2}}}{{{m}_{1}}} \right)}^{2}}={{\left( \frac{3}{1} \right)}^{2}}=\frac{9}{1}\]You need to login to perform this action.
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