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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A man of weight 75 kg is standing in an elevator which is moving with an acceleration of \[5\,m/{{s}^{2}}\] in upward direction the apparent weight of the man will be \[(g=10\,\,m/{{s}^{2}})\] [Pb. PMT 2004]

    A)             1425 N

    B)             1375 N

    C)                         1250 N          

    D)                         1125 N          

    Correct Answer: D

    Solution :

                                The apparent weight,             \[R=m(g+a)=75(10+5)=1125\,N\]


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