JEE Main & Advanced
Physics
NLM, Friction, Circular Motion
Question Bank
Second Law of Motion
question_answer
A man of weight 75 kg is standing in an elevator which is moving with an acceleration of \[5\,m/{{s}^{2}}\] in upward direction the apparent weight of the man will be \[(g=10\,\,m/{{s}^{2}})\] [Pb. PMT 2004]
A) 1425 N
B) 1375 N
C) 1250 N
D) 1125 N
Correct Answer:
D
Solution :
The apparent weight, \[R=m(g+a)=75(10+5)=1125\,N\]