A) \[NaB{{D}_{4}}\] in \[C{{H}_{3}}OH\]
B) \[LiAl{{H}_{4}}\] then \[{{D}_{2}}O\]
C) \[NaB{{D}_{4}}\] in \[C{{H}_{3}}OD\]
D) \[LiAl{{D}_{4}}\] then \[{{D}_{2}}O\]
Correct Answer: A
Solution :
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