A) ethane
B) ethylene
C) butane
D) propane
Correct Answer: A
Solution :
[a] Ethers are reduced by red and P and HI to alkanes through alkyl iodides \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\xrightarrow{red\,P+HI}2{{C}_{2}}{{H}_{5}}I\xrightarrow{red\,P+HI}2{{C}_{2}}{{H}_{6}}\]You need to login to perform this action.
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