A) Primary amine
B) An amide
C) Phenyl isocyanate
D) A higher hydrocarbon
Correct Answer: C
Solution :
[c] \[{{C}_{6}}{{H}_{5}}C{{H}_{3}}\xrightarrow{[O]}\underset{[A]}{\mathop{{{C}_{6}}{{H}_{5}}COOH}}\,\xrightarrow{SOC{{l}_{2}}}\] \[\underset{[B]}{\mathop{{{C}_{6}}{{H}_{5}}COCl}}\,\xrightarrow{Na{{N}_{3}}}\underset{[C]}{\mathop{{{C}_{6}}{{H}_{5}}CO{{N}_{3}}}}\,\] \[\xrightarrow{heat}\underset{Unstable\,Bemzoyl\,nitrene}{\mathop{\left[ {{C}_{6}}{{H}_{5}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\overset{..}{\mathop{N}}\,: \right]}}\,\xrightarrow{{}}\underset{Phenyl\,isocyanate,[D]}{\mathop{{{C}_{6}}{{H}_{5}}NCO}}\,\]You need to login to perform this action.
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