A) lactic acid
B) ethyiamine
C) propylamine
D) alanine
Correct Answer: D
Solution :
[d] \[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{red\,P,\,B{{r}_{2}}}C{{H}_{3}}CHBrCOOH\] \[\xrightarrow{N{{H}_{3}}}\underset{a-Aminopropionic\text{ }acid\text{ }\left( alanine \right)}{\mathop{C{{H}_{3}}CHN{{H}_{2}}COOH}}\,\]You need to login to perform this action.
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