A) \[C{{H}_{3}}COONa\]
B) \[C{{H}_{3}}COOH\]
C) \[C{{H}_{3}}CHO\]
D) \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}-CHO\]
Correct Answer: D
Solution :
[d] \[HC\equiv CH\xrightarrow[HgS{{O}_{4}}]{30(percent)HgS{{O}_{4}}}\underset{[A]}{\mathop{C{{H}_{3}}CHO}}\,\xrightarrow{NaOH}\] \[\underset{[B]}{\mathop{C{{H}_{3}}CHOHC{{H}_{2}}CHO}}\,\]You need to login to perform this action.
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