A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH\]
B) \[C{{H}_{3}}CHOHC{{H}_{2}}C{{H}_{3}}\]
C) \[{{\left( C{{H}_{3}} \right)}_{3}}COH\]
D) \[C{{H}_{3}}C{{H}_{2}}-O-C{{H}_{2}}C{{H}_{3}}\]
Correct Answer: B
Solution :
[b] \[{{C}_{4}}{{H}_{8}}\xrightarrow[(-{{H}_{2}}O)]{conc.\,{{H}_{2}}S{{O}_{4}}}{{C}_{4}}{{H}_{10}}O\xrightarrow{oxidation}\] \[{{C}_{4}}{{H}_{8}}O\left( R-COC{{H}_{3}} \right)\] Thus \[{{C}_{4}}{{H}_{8}}O\] should be \[C{{H}_{3}}C{{H}_{2}}COC{{H}_{3}}\] hence \[{{C}_{4}}{{H}_{10}}O\] should be \[C{{H}_{3}}C{{H}_{2}}CHOHC{{H}_{3}}\]You need to login to perform this action.
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