A) 1mA
B) 2mA
C) 3mA
D) 4mA
Correct Answer: A
Solution :
[a] RMS value over one cycle=RMS value over AB. \[0\le t\le 15\] \[i(t)=\sqrt{5}\,{{t}^{2}}c\] \[{{i}_{rms}}=\sqrt{<{{i}^{2}}>}=\sqrt{\frac{5\int\limits_{0}^{1}{\,{{t}^{4}}dt}}{\int\limits_{0}^{1}{dt}}}=\,1\,mA\]You need to login to perform this action.
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