A) \[\frac{E}{R\sqrt{LC}}\]
B) \[\frac{ER}{2\sqrt{LC}}\]
C) \[\frac{E\sqrt{LC}}{2R}\]
D) \[\frac{E\sqrt{LC}}{R}\]
Correct Answer: D
Solution :
[d] Current in inductor\[=\frac{E}{R}\] \[\therefore \] its energy\[=\frac{1}{2}\frac{L{{E}^{2}}}{{{R}^{2}}}\] Same energy is later stored in capacitor \[\frac{{{Q}^{2}}}{2C}=\frac{1}{2}\frac{L{{E}^{2}}}{{{R}^{2}}}\Rightarrow Q=\sqrt{LC}\frac{E}{R}\]
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