A) \[\begin{align} & \xrightarrow{{{I}_{c}}} \\ & \xrightarrow[{{I}_{R}}]{} \\ \end{align}\]
B) \[\xleftarrow{{{I}_{C}}}\xrightarrow{{{I}_{R}}}\]
C)
D)
Correct Answer: A
Solution :
[a] Since the cpacitor is connected in series to the resistor, current \[{{I}_{C}}\] from the supply and \[{{I}_{R}}\]through the resistor is in phase as represented by choice [a].You need to login to perform this action.
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