A) 120 volts
B) 220 volts
C) 30 volts
D) 90 volts
Correct Answer: A
Solution :
[a] Since \[\frac{{{V}_{s}}}{{{V}_{p}}}=\frac{{{N}_{s}}}{{{N}_{p}}}\] Where \[{{N}_{s}}\] = No. of turns across primary coil = 50 \[{{N}_{p}}\] = No. of turns across secondary coil = 1500 and \[{{V}_{p}}=\frac{d\phi }{dt}=\frac{d}{dt}\,({{\phi }_{0}}+4t)=\,4\Rightarrow \,V=\frac{1500}{50}\times 4\] =120 VYou need to login to perform this action.
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