question_answer

What is the amount of power delivered by the ac source in the circuit shown (in watts).

A) 500 watt 

B) 1014 watt   

C) 1514 watt

D) 2013 watt            

Correct Answer: C

Solution :

[c] \[{{i}_{1\,rms}}=\frac{{{E}_{rms}}}{\sqrt{X_{C}^{2}+R_{1}^{2}}}=\frac{130}{13}=10A\] \[{{i}_{2\,rms}}=\frac{{{E}_{rms}}}{\sqrt{X_{L}^{2}+R_{2}^{2}}}=13\,A\] Power dissipated    \[={{i}^{2}}_{1\,rms}\,{{R}_{1}}+{{i}^{2}}_{2\,rms}{{R}_{2}}={{10}^{2}}\times 5+{{13}^{2}}+6\] = power delivered by battery \[=500+169\times 6=1514\,watt\]