JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Self Evaluation Test - Alternating Current

  • question_answer
    An inductor \[20\times {{10}^{-3}}\] Henry, a capacitor \[100\,\mu F\]and a resistor \[50\,\Omega \] are connected in series across a source of EMF V=10 sin 314t. If resistance is removed from the circuit and the value of  inductance is doubled, then the variation of current with time in the new circuit is -

    A) \[0.52\text{ }cos\text{ }314t\]

    B) \[0.52\text{ }sin\text{ }314t\]

    C) \[0.52\,\sin \,(314t+\pi /3)\]

    D) None of these

    Correct Answer: A

    Solution :

    [a] \[{{x}_{C}}-{{x}_{L}}=31.85-2(6.28)=19.29\] \[{{I}_{m}}=\frac{10}{19.29}=0.52\] Hence \[I=0.52\,\sin \,(314t+\pi /2)=0.52\,\cos \,314\,t\]


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