A) 300V, 15A
B) 450V, 15A
C) 450V, 13.5A
D) 600V, 15A
Correct Answer: B
Solution :
[b] Efficiency \[\eta =\frac{{{V}_{s}}{{I}_{s}}}{{{V}_{p}}{{I}_{p}}}\Rightarrow \,0.9\,=\frac{{{V}_{s}}(6)}{3\times {{10}^{3}}}\Rightarrow \,{{V}_{s}}\] = 450V As \[{{V}_{P}}{{I}_{p}}=3000\] So \[{{I}_{p}}=\frac{3000}{{{V}_{p}}}=\frac{3000}{200}=A=15A\]
You need to login to perform this action.
You will be redirected in
3 sec
