A) \[8f\]
B) \[f/2\sqrt{2}\]
C) \[f/2\]
D) \[f/4\]
Correct Answer: B
Solution :
[b] We know that frequency of electrical oscillation in L.C. circuit is \[f=\frac{1}{2\pi }\sqrt{\frac{1}{LC}}\] Now, L=2L & C=4C \[f'=\frac{1}{2\pi }\sqrt{\frac{1}{2L\cdot 4C}}=\frac{1}{2\pi }\sqrt{\frac{1}{LC}}\times \frac{1}{2\sqrt{2}}\Rightarrow \,f'\] \[=\frac{1}{2\sqrt{2}}\times f\]
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