A) 3.6 ampere
B) 2.8 ampere
C) 2.5 ampere
D) 5.0 ampere
Correct Answer: D
Solution :
[d] \[\frac{{{V}_{2}}}{{{V}_{1}}}=0.8\frac{{{I}_{1}}}{{{I}_{2}}}\,\Rightarrow \,\frac{{{V}_{2}}{{I}_{2}}}{{{V}_{1}}{{I}_{1}}}=0.8\] \[{{V}_{1}}=220\,V,\,{{I}_{2}}=2.0A,\,{{V}_{2}}=440\,V\] \[{{I}_{1}}=\frac{{{V}_{2}}{{I}_{2}}}{{{V}_{1}}}\times \frac{10}{8}=\frac{440\times 2\times 10}{220\times 8}=5A\]
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