A) \[C{{H}_{3}}C{{H}_{2}}OH\]
B) \[{{C}_{2}}{{H}_{6}}\]
C) \[C{{H}_{3}}CH=NOH\]
D) \[C{{H}_{3}}COOH\]
Correct Answer: D
Solution :
[d] \[1{}^\circ \] Nitroalkanes on hydrolysis with boiling 85% \[{{H}_{2}}S{{O}_{4}}\] give acids. \[C{{H}_{3}}C{{H}_{2}}N{{O}_{2}}+{{H}_{2}}O+{{H}_{2}}S{{O}_{4}}\xrightarrow{heat}\] \[C{{H}_{3}}COOH+{{\left[ N{{H}_{3}}OH \right]}^{+}}HSO_{4}^{-}\]You need to login to perform this action.
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