A) \[{{\left( C{{H}_{3}} \right)}_{3}}CN{{H}_{2}}\]
B) \[{{\left( C{{H}_{3}} \right)}_{3}}CNHD\]
C) \[{{\left( C{{H}_{3}} \right)}_{3}}CN{{D}_{2}}\]
D) no reaction
Correct Answer: C
Solution :
[c] Remember that in Hofmann rearrangement, the two original H atoms of the \[-CON{{H}_{2}}\] group are removed by base \[\left( O{{H}^{-}} \right)\] and new H's are derived from\[{{H}_{2}}O\]. \[{{(C{{H}_{3}})}_{3}}C-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-N{{H}_{2}}\xrightarrow[(ii)\,{{D}_{2}}O]{(i)\,O{{D}^{-}}/B{{r}_{2}}}{{(C{{H}_{3}})}_{3}}C-N{{D}_{2}}\]You need to login to perform this action.
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