Above compounds can be differentiated by using the reagent:
A) \[NaOH\], Tollen's reagent, \[FeC{{l}_{3}}\]
B) \[Cr{{O}_{3}}\] Tollen's reagent, \[FeC{{l}_{3}}\]
C) Tollen's reagent, \[Cr{{O}_{3}},FeC{{l}_{3}}\]
D) Na, Tollen's reagent, \[FeC{{l}_{3}}\]
Correct Answer: B
Solution :
[b]
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