A) 9.8 g
B) 4.9 g
C) 19.6 g
D) 3.2 g
Correct Answer: B
Solution :
[b] The ionic equation for oxidation of Mohr 's salt is \[F{{e}^{2+}}\xrightarrow{{}}F{{e}^{3+}}+{{e}^{-}}\] Now Eq. of Mohr's salt \[=\frac{392}{1}=392\] Strength = Normality \[\times \] Eq. mass \[=\frac{1}{20}\times 392=19.6g/lit\] Thus for preparing 250 ml of N/20 Mohr's salt solution, Mohr's salt needed \[=\frac{19.6}{1000}\times 250=4.9g\]You need to login to perform this action.
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