A) \[CuC{{l}_{2}}\]
B) \[FeC{{l}_{3}}\]
C) \[Cu{{(N{{O}_{3}})}_{2}}\]
D) \[Fe{{(N{{O}_{3}})}_{3}}\]
Correct Answer: B
Solution :
[b] \[F{{e}^{3+}}\], radical gives blood red with \[CN{{S}^{-}}\] \[F{{e}^{3+}}+3CN{{S}^{-}}\xrightarrow{{}}\underset{\begin{smallmatrix} Ferric\text{ }sulphocyamde \\ \left( Blood\text{ }red\text{ }colouration \right) \end{smallmatrix}}{\mathop{Fe{{(CNS)}_{3}}}}\,\] \[F{{e}^{3+}}\] gives blue colour on treatment with \[{{K}_{4}}[Fe{{(CN)}_{6}}]\] \[4F{{e}^{3+}}+3{{K}_{4}}\left[ Fe{{\left( CN \right)}_{6}} \right]\xrightarrow{{}}\] \[\underset{\begin{smallmatrix} Ferricferrocyanide \\ \left( Prussian\text{ }blue \right) \end{smallmatrix}}{\mathop{12{{K}^{+}}+F{{e}_{4}}{{\left[ Fe{{\left( CN \right)}_{6}} \right]}_{3}}}}\,\] \[C{{l}^{-}}\] radical gives chromyl chloride test.You need to login to perform this action.
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