A) 50
B) 78.4
C) 80
D) 39.2
Correct Answer: A
Solution :
[a] Eq of \[KMn{{O}_{4}}\] used \[=\frac{50\times 1}{1000\times 10}=0.005\] \[\therefore \] Eq of FAS reacted = 0.005 \[\therefore \] weight of FAS needed \[=0.005\times 392=1.96g\]You need to login to perform this action.
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