2. Questions Bank
  3. NEET
  4. Chemistry
  5. Analytical Chemistry

NEET Chemistry Analytical Chemistry Question Bank Self Evaluation Test - Analytical Chemistry

  • question_answer
    For preparing 250 mL of N/20 solution of Mohr 's salt, the amount of Mohr's salt needed is

    A) 9.8 g                

    B) 4.9 g

    C) 19.6 g              

    D) 3.2 g

    Correct Answer: B

    Solution :

    [b] The ionic equation for oxidation of Mohr 's salt is \[F{{e}^{2+}}\xrightarrow{{}}F{{e}^{3+}}+{{e}^{-}}\] Now Eq. of Mohr's salt \[=\frac{392}{1}=392\] Strength = Normality \[\times \] Eq. mass \[=\frac{1}{20}\times 392=19.6g/lit\] Thus for preparing 250 ml of N/20 Mohr's salt solution, Mohr's salt needed \[=\frac{19.6}{1000}\times 250=4.9g\]


You need to login to perform this action.
You will be redirected in 3 sec spinner