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NEET Chemistry Analytical Chemistry Question Bank Self Evaluation Test - Analytical Chemistry

  • question_answer
    Three separate samples of a solution of a single salt gave these results. One formed a white precipitate with excess ammonia solution, one formed a white precipitate with dil. \[NaCl\] solution and one formed a black precipitate with \[{{H}_{2}}S\]. The salt could be

    A) \[AgN{{O}_{3}}\]        

    B) \[Pb{{\left( N{{O}_{3}} \right)}_{2}}\]

    C) \[Hg{{\left( N{{O}_{3}} \right)}_{2}}\]              

    D) \[MnS{{O}_{4}}\]

    Correct Answer: B

    Solution :

    [b] \[Pb{{(N{{O}_{3}})}_{2}}+2N{{H}_{4}}OH\to \]  \[\underset{\left( white\text{ }ppt \right)}{\mathop{Pb{{(OH)}_{2}}}}\,\downarrow +2N{{H}_{4}}N{{O}_{3}}\] \[Pb{{(N{{O}_{3}})}_{2}}+2HCl\to \underset{\left( white\text{ }ppt \right)}{\mathop{PbC{{l}_{2}}\downarrow }}\,+2HN{{O}_{3}}\] \[Pb{{(N{{O}_{3}})}_{2}}+{{H}_{2}}S\to \underset{\left( black \right)}{\mathop{PbS\downarrow }}\,+2HN{{O}_{3}}\]


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