A) \[X=C{{O}_{2}},Y=C{{l}_{2}}\]
B) \[X=C{{l}_{2}},Y=C{{O}_{2}}\]
C) \[X=C{{l}_{2}},Y={{H}_{2}}\]
D) \[X={{H}_{2}},Y=C{{l}_{2}}\]
Correct Answer: C
Solution :
[c] \[C{{l}_{2}}+{{H}_{2}}O\to HCl+HClO\] \[HCl+AgN{{O}_{3}}\to \underset{White\text{ }ppt}{\mathop{AgCl\downarrow }}\,+HN{{O}_{3}}\] \[Mg+2HCl\to MgC{{l}_{2}}+{{H}_{2}}\uparrow \] Hence X is \[C{{l}_{2}}\] and Y is \[{{H}_{2}}\]You need to login to perform this action.
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