NEET Chemistry Analytical Chemistry Question Bank Self Evaluation Test - Analytical Chemistry

  • question_answer
    Prussian blue is formed when

    A) ferrous sulphate reacts with \[FeC{{l}_{3}}\]

    B) ferric sulphate reacts with \[{{K}_{4}}Fe{{\left( CN \right)}_{6}}\]

    C) ferrous ammonium sulphate reacts with \[FeC{{l}_{3}}\]

    D) ammonium sulphate reacts with \[N{{O}_{2}}\]

    Correct Answer: B

    Solution :

    [b] \[2F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+3{{K}_{4}}[(Fe{{(CN)}_{6}}]\to \] \[\underset{Prussian\text{ }blue}{\mathop{F{{e}_{4}}{{[Fe{{\left( CN \right)}_{6}}]}_{3}}}}\,+6{{K}_{2}}S{{O}_{4}}\]


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