A) 26.32%
B) 40%
C) 53.6%
D) 63.6%
Correct Answer: A
Solution :
[a] Percentage of nitrogen by Kjeldahl's method \[=\frac{1.4\times N\times V}{Wt.\text{ }of\text{ }organic\text{ }compound}\] \[=\frac{1.4\times 20}{0.532}\times \frac{1}{2}=26.32%\]%You need to login to perform this action.
You will be redirected in
3 sec