A) HCHO
B) \[C{{H}_{3}}OH\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\]
D) \[{{(COOH)}_{2}}\]
Correct Answer: A
Solution :
[a] % ratio of \[C:H\] is \[6:1\] and \[C:O\] is \[3:4\] or 6:8 \[\therefore \] % ratio of \[C:H:O\text{ }is\text{ }6:1:0\] (Total =15) % of \[C=\frac{6}{15}\times 100=40\] 40/12=3. 33=1 % of \[H=\frac{1}{15}\times 100=6.6\] 6.6/1=6.6=2 % of \[O=\frac{8}{15}\times 100=53.3\] 53.3/16=3.3=1 simple ratio: \[C{{H}_{2}}O\] \[\therefore \] The compound is HCHO
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