A) \[HCO_{3}^{-}\]
B) \[CO_{3}^{2-}\]
C) Qxalate
D) Acetate
Correct Answer: C
Solution :
[c] \[N{{a}_{2}}{{C}_{2}}{{O}_{4}}+{{H}_{2}}S{{O}_{4}}\to \] \[N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O+CO+C{{O}_{2}}\] CO burns with blue flame \[2CO+{{O}_{2}}\to 2C{{O}_{2}}\] \[N{{a}_{2}}{{C}_{2}}{{O}_{4}}+{{H}_{2}}S{{O}_{4}}\left( dil \right)\to \] \[N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}{{C}_{2}}{{O}_{4}}\] \[2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}+5{{H}_{2}}{{C}_{2}}{{O}_{4}}\to \] \[{{K}_{2}}S{{O}_{4}}+2MnS{{O}_{4}}+8{{H}_{2}}O+10C{{O}_{2}}\]You need to login to perform this action.
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