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NEET Chemistry Analytical Chemistry Question Bank Self Evaluation Test - Analytical Chemistry

  • question_answer
    2.79 g of an organic compound when heated in Carius tube with cone. \[HN{{O}_{3}}\] and \[{{H}_{2}}P{{O}_{4}}\] formed is converted into \[MgN{{H}_{4}}.P{{O}_{4}}\]ppt. The ppt. on heating gave 1.332 g of \[M{{g}_{2}}{{P}_{2}}{{O}_{7}}\]. The percentage of P in the compound is

    A) 23.33%            

    B) 13.33%

    C) 33.33%            

    D) 26.66%

    Correct Answer: B

    Solution :

    [b] Percentage of P \[=\frac{62}{222}\times \frac{wt.of\,M{{g}_{2}}{{P}_{2}}{{O}_{7}}}{wt.\text{ }of\text{ }compound}\times 100\] \[=\frac{62}{222}\times \frac{1.332}{2.79}\times 100=13.33%\]%


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