A) \[Sn\left( OH \right)Cl\]
B) \[Sb\left( OH \right)C{{l}_{2}}\]
C) \[SbOCl\]
D) \[Sb{{\left( OH \right)}_{2}}Cl\]
Correct Answer: C
Solution :
[c] \[S{{b}_{2}}{{S}_{3}}+6HCl\to 2SbC{{l}_{3}}+3{{H}_{2}}S\] \[SbC{{l}_{3}}+6{{H}_{2}}O\to \underset{ppt\text{ }\left( White \right)}{\mathop{SbOCl}}\,+2HCl\]You need to login to perform this action.
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