NEET Chemistry Analytical Chemistry Question Bank Self Evaluation Test - Analytical Chemistry

  • question_answer
    A substance on treatment with dil. \[{{H}_{2}}S{{O}_{4}}\] liberates a colourless gas which produces
    (I) turbidity with baryta water and
    (II) turns acidified dichromate solution green.
    The reaction indicates the presence of

    A) \[CO_{3}^{2-}\]                      

    B) \[{{s}^{2-}}\]

    C) \[SO_{3}^{2-}\]                      

    D) \[NO_{3}^{-}\]

    Correct Answer: C

    Solution :

    [c] \[N{{a}_{2}}S{{O}_{3}}+2HCl\left( dil \right)\to \] \[2NaCl+{{H}_{2}}O+S{{O}_{2}}\] \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+{{H}_{2}}S{{O}_{4}}+3S{{O}_{2}}\to \] \[\underset{Green}{\mathop{{{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}+{{H}_{2}}O}}\,\]


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