JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Self Evaluation Test - Application of Derivatives

  • question_answer
    If at any instant t, for a sphere, r denotes the radius, S denotes the surface area and V denotes the volume, then what is \[\frac{dV}{dt}\] equal to?

    A) \[\frac{1}{2}S\frac{dr}{dt}\]

    B) \[\frac{1}{2}r\frac{dS}{dt}\]

    C) \[r\frac{dS}{dt}\]

    D) \[\frac{1}{2}{{r}^{2}}\frac{dS}{dt}\]

    Correct Answer: B

    Solution :

    [b] Surface area of sphere \[S=4\pi {{r}^{2}}\] Differentiate both sides w.r.t. t? \[\Rightarrow \frac{dS}{dt}=\frac{8\pi rdr}{dt}\] and Volume \[=V=\frac{4}{3}\pi {{r}^{3}}\] \[\Rightarrow \frac{dV}{dt}=\frac{4}{3}\pi .3{{r}^{2}}\frac{dr}{dt}=4\pi {{r}^{2}}\frac{dr}{dt}\] \[=\frac{4\pi {{r}^{2}}}{8\pi r}.\frac{dS}{dt}=\frac{1}{2}r\frac{dS}{dt}\]


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