A) 1
B) 2
C) 3
D) No tangent is parallel to x-axis
Correct Answer: A
Solution :
[a] Let \[y={{x}^{2}}-4x+3\] Differentiate both sides w.r.t. ?x? \[\frac{dy}{dx}=2x-3\] So, slope \[=2x-3\] Since, tangent is \[\parallel \] to x = axis \[\therefore \] slope = 0 \[\Rightarrow \frac{dy}{dx}=0\Rightarrow 2x-3=0\Rightarrow x=\frac{3}{2}\] \[\Rightarrow \] one tangentYou need to login to perform this action.
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