A) ¼
B) ½
C) 3/4
D) 1
Correct Answer: B
Solution :
[b] \[x={{e}^{\sin \,\,y}}\Rightarrow In\,\,x=\sin \,\,y\Rightarrow \frac{1}{x}\frac{dx}{dy}=\cos y\] \[\therefore \] slope of normal at (1, 0) \[=-\frac{dx}{dy}=-1\times \cos 0=-1\] \[\therefore \] Equation of normal is \[y-0=-1(x-1)\] \[\Rightarrow x+y=1\] Which forms triangle of area \[\frac{1}{2}\] with axes.You need to login to perform this action.
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