A) Has a local maximum
B)
C) Is discontinuous
D) None of these
Correct Answer: B
Solution :
[b] \[f(0)=\sin 0=0,f({{0}^{+}})\to {{0}^{+}}\] \[f({{0}^{-}})=\underset{x\to {{0}^{-}}}{\mathop{\lim }}\,\sin ({{x}^{2}}-3x)=\underset{h\to 0}{\mathop{\lim }}\,\sin ({{h}^{2}}+3h)\to {{0}^{+}}\] Thus, \[f({{0}^{+}})>f(0)\] and \[f({{0}^{-}})>f(0)\]. Hence, \[x=0\] is a point of minima. Has a local minimumYou need to login to perform this action.
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