A) 0
B) 1
C) 2
D) None of these
Correct Answer: A
Solution :
[a] \[y={{\sin }^{-1}}({{\sin }^{2}}x)\] \[\frac{dy}{dx}=\frac{2\sin x\cos x}{\sqrt{1-{{\sin }^{4}}x}}\Rightarrow \frac{dy}{dx}=\frac{\sin 2x}{\sqrt{1-{{\sin }^{4}}x}}\] \[at\,\,x=0,\frac{dy}{dx}=0\]You need to login to perform this action.
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