A) 1 s
B) \[(log\,\,10)s\]
C) \[2\text{(}log\text{ }10)s\]
D) \[10s\]
Correct Answer: B
Solution :
[b] Given velocity is \[v=s+1\] Since, velocity \[=\frac{ds}{dt}\] \[\therefore \frac{ds}{dt}=s+1\Rightarrow \frac{ds}{s+1}=dt\] Integrate both side we get \[\log (s+1)=t\] At \[s=9\,\,m,\] \[t=\log (10)\] secondYou need to login to perform this action.
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