A) \[68\,\,c{{m}^{2}}\]
B) \[70\,\,c{{m}^{2}}\]
C) \[71.25\,\,c{{m}^{2}}\]
D) \[72.25\,\,c{{m}^{2}}\]
Correct Answer: D
Solution :
[d] Let one side of quadrilateral be x and another side be y so, \[2(x+y)=34\] or, \[(x+y)=17....(i)\] We know from the basic principle that for a given perimeter square has the maximum area, so, x = y and putting this value in equation (i) \[x=y=\frac{17}{2}\] Area \[=x.y=\frac{17}{2}\times \frac{17}{2}=\frac{289}{4}=72.25\]
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