A) a = b = 0
B) a = b = 1
C) a = b = 2
D) a = b = -1
Correct Answer: C
Solution :
[c] \[y=a{{x}^{2}}-6x+b\] passes through (0, 2). i.e., \[2=0-0+b\] or \[b=2\] Again, \[\frac{dy}{dx}=2ax-6\] At \[x=\frac{3}{2},\frac{dy}{dx}=3a-6\] Since tangent is parallel to x-axis, \[\frac{dy}{dx}=0\] or \[3a-6=0\] or \[a=2\]. Hence, \[a=2,b=2\].You need to login to perform this action.
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