A) 6
B) 1
C) 4
D) 2
Correct Answer: D
Solution :
[d] \[y=\frac{36}{{{x}^{2}}},x=6,x=9\] Desired area \[=\int\limits_{6}^{9}{\frac{36}{{{x}^{2}}}dx}\] \[=-36\left[ \frac{1}{9}-\frac{1}{6} \right]=2\]You need to login to perform this action.
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