A) \[\frac{8{{E}_{g}}}{9}\]
B) \[\frac{15{{E}_{g}}}{16}\]
C) \[\frac{35{{E}_{g}}}{36}\]
D) \[\frac{48{{E}_{g}}}{49}\]
Correct Answer: B
Solution :
[b] To obtain 6 spectral line, as electron must be excited to fourth orbit with energy \[\frac{{{E}_{g}}}{16},\] so that the difference is \[\frac{15{{E}_{g}}}{16},\]You need to login to perform this action.
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