A) 2040 eV
B) 0.201 eV
C) 510 eV
D) 1020 eV
Correct Answer: D
Solution :
[d] For H atom \[{{E}_{2}}-{{E}_{1}}=10.2eV\] \[\text{For }Z=10,\] \[{{E}_{1}}=\frac{-13.6\times {{10}^{2}}}{{{1}^{2}}}=-1360eV\] \[{{E}_{2}}=\frac{-13.6\times {{10}^{2}}}{{{2}^{2}}}=-3.4\times 100=-340eV\] \[\therefore {{E}_{2}}-{{E}_{1}}=-340-\left( -1360 \right)=1020eV\]You need to login to perform this action.
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